this post was submitted on 15 May 2025
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[–] ccunning@lemmy.world 100 points 3 weeks ago (3 children)

Fools!
…limiting themselves to Euclidean geometry…

[–] mmddmm@lemm.ee 28 points 3 weeks ago (1 children)

Only one of them is limiting himself to Euclidean geometry. The others are perfectly calm.

[–] ccunning@lemmy.world 2 points 3 weeks ago (1 children)

“…waving a gun around!?…”

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[–] gedaliyah@lemmy.world 70 points 3 weeks ago

Saddle shaped universe confirmed

[–] owenfromcanada@lemmy.ca 55 points 3 weeks ago (4 children)

Looks like a tetrahedron to me.

[–] smuuthbrane@sh.itjust.works 25 points 3 weeks ago

Exactly! The diagram is simply a schematic.

[–] Isa@feddit.org 6 points 3 weeks ago

Just wanted to … nevermind.

Too late is too is too late is …

[–] rdri@lemmy.world 4 points 3 weeks ago (1 children)

That implies one person is observing 3 other people from the above (or flying over), which is not exactly trivial.

[–] owenfromcanada@lemmy.ca 3 points 3 weeks ago

Nobody said it would be easy

[–] untakenusername@sh.itjust.works 3 points 3 weeks ago

exactly what I came here to say

[–] xia@lemmy.sdf.org 36 points 3 weeks ago (1 children)
[–] bampop@lemmy.world 11 points 3 weeks ago

ikr? It's like some people don't even recognize a tetrahedron

[–] RandomStickman@fedia.io 23 points 3 weeks ago (2 children)
[–] GoodLuckToFriends@lemmy.today 11 points 3 weeks ago (1 children)

Pffft, Dnd had the 'first diagonal 5, second diagonal 10' rule. It worked well enough, aye?

[–] brown567@sh.itjust.works 6 points 3 weeks ago (3 children)

It doesn't anymore =(

5e uses diagonal = 5'

[–] edgemaster72@lemmy.world 5 points 3 weeks ago (1 children)

Alternating diagonals is in the (2014) DMG as an optional rule at least

[–] brown567@sh.itjust.works 5 points 3 weeks ago

Oh good! Octagons are a much better approximation of a circle than squares

[–] Zagorath@aussie.zone 4 points 3 weeks ago

4e just used "squares" instead of 5 feet, but it, like 5e, used chebyshev distances.

Pathfinder 2e uses alternating diagonals though.

[–] Vespair@lemm.ee 4 points 3 weeks ago

Well anything after 3.5e is a watered-down, bastardized version of the game anyway.

[–] TheBat@lemmy.world 3 points 3 weeks ago

D&D still doesn't have hexagons?

[–] BombOmOm@lemmy.world 17 points 3 weeks ago

Well you see, space isn't flat in this very localized area!

[–] Randelung@lemmy.world 16 points 3 weeks ago (1 children)
[–] Mistic@lemmy.world 10 points 3 weeks ago* (last edited 3 weeks ago) (2 children)

Equal sides in a triangle are only possible if the corners are equal. So, 60⁰ each.

But its height cannot be half of base because of the same Pythagorean theorem

(1,5)²+(1,5/2)²=2,8125

sqrt(2,8125) ≈ 1,677, which is half of a diagonal

So, we get 4 sides that are 1,5 in a parallelogram, but diagonals are 1,5 and 3,354, as opposed to both being 1,5 as shown on the picture

TL;DR: Won't work because Pythagorean theorem

[–] Obi@sopuli.xyz 4 points 3 weeks ago (2 children)

It's funny how we say "because of such and such theorem" as if if some greek dude didn't come up with his little story, the height could totally be half of base.

[–] bss03@infosec.pub 2 points 3 weeks ago

Decolonialize Maths!

We do need short names, but they don't all have to be wyt guys. Pre-globalization, I'm sure many true maths statements were independently discovered by many people.

[–] rowinxavier@lemmy.world 3 points 3 weeks ago (6 children)
[–] kryptonianCodeMonkey@lemmy.world 3 points 3 weeks ago (1 children)

Yes, it is possible with a 3-sided pyramid, i.e. tetrahedron. If we dont look at all 4 points as being on the same plane but 2 opposite corners being offset above or below the other two, this could totally be a tatrahedron.

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[–] DavidGarcia 15 points 3 weeks ago

calm down, they're constraints on distance, not distance

[–] Danitos@reddthat.com 13 points 3 weeks ago

Funnily enough, this is valid under Chebyshev metric, same that kings in chess follow.

[–] untakenusername@sh.itjust.works 13 points 3 weeks ago (4 children)

if the people were aranged in 3d in the shape of a tetrahedron (triangular pyramid) this would work out fine

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[–] LovableSidekick@lemmy.world 12 points 3 weeks ago (1 children)

Tetrahedrons man, tetrahedrons.

[–] intensely_human@lemm.ee 3 points 3 weeks ago (1 children)

So this makes me wonder if one could force a move into a higher dimension by somehow constraining a set of connected distances in this way.

Sort of like protein folding as a way to bootstrap a dimensional jump.

[–] LovableSidekick@lemmy.world 3 points 3 weeks ago* (last edited 3 weeks ago)

You might like And He Built a Crooked House by Robert Heinlein - the story of a tesseract-shaped house that folds itself into a real tesseract during an earthquake.

https://en.wikipedia.org/wiki/And_He_Built_a_Crooked_House

[–] regdog@lemmy.world 9 points 3 weeks ago

Middle one should be the square root of 4.5 meters, or 2.12 meters

[–] SuperNovaStar@lemmy.blahaj.zone 9 points 3 weeks ago

You're all thinking too two-dimensionally. Clearly the people are being instructed to arrange themselves into a tetrahedron.

[–] mumblerfish@lemmy.world 8 points 3 weeks ago (1 children)

What? Everytime I meet other people we always arange ourselves in the shape of a simplex of the appropriate dimension. Doesn't everyone?

[–] davidagain@lemmy.world 5 points 3 weeks ago* (last edited 3 weeks ago) (5 children)

So the fifth person to arrive moves to the centre of the tetrahedron and shifts roughly 1.299m into the past or future.

I have a few questions.

  1. How do you attain time offset?
  2. Doesn't that make conversation difficult?
  3. What even is the fifth dimension?
  4. How do you convert a distance in metres into a distance in time? You would surely then have a universal m/s? Oh, wait, there is a universal speed, it's the speed of light, which means 1.299m is equivalent to about 4.3 billionths of a second, which is considerably less impressive for question 1 and just not at all problematic for question 2.
  5. If you're using very fast motion for your time offset, doesn't that make conversation even more difficult? How fast would you need to be going to dilate time for a few billionths of a second? Doesn't Heisenberg uncertainty start to have an impact here? How can you be sure you got it right?
[–] ivanafterall@lemmy.world 4 points 3 weeks ago (1 children)

If you have to ask, you wouldn't understand.

[–] davidagain@lemmy.world 3 points 3 weeks ago

If I understood, I wouldn't have to ask.

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[–] middlemanSI@lemmy.world 3 points 3 weeks ago
[–] Cruxifux 3 points 3 weeks ago

This is so good hahaha

[–] Luffy879@lemmy.ml 2 points 3 weeks ago (3 children)

Explanation:

So, Theres the sentence of Pythagoras. It says that c^2^ = a^2^ + b^2^ when the triangle has a 90° corner

Since a square is just 2 triangles, it applies. That means c (the distance from Person a to Person c) should be √(2×1.90^2^). But that is 2.7m.

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