Xavienth

joined 4 years ago
[–] Xavienth@lemmygrad.ml 1 points 15 hours ago

A freefall from space has not been demonstrated. The 40 km jumps done are well below the 100 km Karman line (accepted as the definition of space, but it's mostly an on-paper thing) and much lower than the 400-600 km orbit of the ISS. The thing about these jumps is they begin at ~0 km/h already in or just above where the atmosphere is significant. If you fall from significantly higher than this, you have a lot of altitude in freefall and the atmosphere is so thin that you won't slow down enough for it to matter, leading to a very high speed entry into the lower atmosphere.

Baumgartner's top speed was Mach 1.25. If you fell from the ISS, your speed when you got to where he began his fall would be around Mach 6-8.

[–] Xavienth@lemmygrad.ml 1 points 15 hours ago

If you fell straight down from the height of the orbit of the ISS, by the time you reached the thicker parts of the atmosphere, you would be travelling at around 2 km/s. Unprotected, this is enough energy to raise your temperature by 500 °C, but not all of that energy would actually go into you so you would be a little bit cooler. But suffice it to say, if you have to get off the ISS without a capsule, you're cooked.

[–] Xavienth@lemmygrad.ml 2 points 15 hours ago

The intersection point of your orbit would be fixed in space, but because you have added or removed energy from yourself, your orbital period will be slightly different. When you come back around, the station will be a little bit ahead or behind where it was last orbit.

With each subsequent orbit, this gap would grow until you're on completely opposite sides of the planet at the intersection point, and then it would shrink. Eventually, the difference would come back around to zero and you would hit the station.

In theory, anyway. In reality, perturbations in your and the ISS' orbits would almost ensure you never hit it again for a very long time, if ever.

[–] Xavienth@lemmygrad.ml 2 points 4 days ago

Billionaires are the law

[–] Xavienth@lemmygrad.ml 1 points 4 days ago

It's likely we won't actually know with certainty until its next pass in 2028. The window for observation is closing, especially for smaller telescopes. Even with our best telescopes, we have until about June, and these are very busy telescopes.

[–] Xavienth@lemmygrad.ml 8 points 4 days ago

Legend has it qrstuv has still never elaborated on the abbreviations policy to this day...

Sometimes, on especially cold winter nights, some say you can still hear qrstuv whispering about the name.

[–] Xavienth@lemmygrad.ml 1 points 4 days ago

I find the triangle problem a bit silly. There's a clever insight to easily solve it, but the alternative, systematic approach is not exactly high-level knowledge.

[–] Xavienth@lemmygrad.ml 2 points 5 days ago* (last edited 5 days ago)

Well, the way I see it, there's a few possibilities, with different parties to blame.

Mechanical error would be the fault of Delta/Endeavor. This is a tested plane with many many flight hours. A mechanical issue could only be a maintenance error. But so far there have been no confirmed reports to suggest this.

Pilot error would be the fault of Endeavor's training.

It could possibly be some freak gust of wind right at the worst moment. Second-to-second weather can be hard to deal with, especially at 40 km/h.

Or if ATC failed to adequately convey the conditions for the pilots to make an informed decision, that would be the fault of the GTA airport authority/Navcan.

TL;DR with the evidence we have so far, we're looking at pilot error, or weather that was just wrong place wrong time.

[–] Xavienth@lemmygrad.ml 4 points 5 days ago

The precise mechanism is beyond me, but suffice it to say that light is affected by gravity.

If you imagine throwing a ball in space in a straight line near a massive body (like a planet), the ball will curve and its new straight path will now be permanently deviated from its original straight line.

Now imagine instead of throwing a ball, you're emitting rays of light in all directions near a black hole. Light you emit towards the black hole will be lost to it, but light you emitted at an angle to the black hole will swing around it, just like the ball. If you imagine all the light you emitted slightly to the right, left, up, and down doing this, you can imagine that an observer on the other side could see all that light, appearing as though you were slightly right, left, up, and down from the black hole at the same time. This is what creates the ring.

[–] Xavienth@lemmygrad.ml 1 points 5 days ago (1 children)

To half the users in this thread, normal people use computers as a means to an end.

"If you're not prepared to get your hands dirty this OS is not for you" you've already lost me, this is unhinged behaviour. You have one life and you choose to spend it fixing your computer so it will do the same things except slightly differently.

But I know this is an unpopular opinion for Linux users.

[–] Xavienth@lemmygrad.ml 2 points 5 days ago

And not just "a beach on the ocean", but literally just the open ocean.

[–] Xavienth@lemmygrad.ml 1 points 6 days ago

Funny. I went to Walmart a month or so ago and picked up a crown of broccoli, but it didn't have a tag. The self checkout attendant just estimated the cost (which was slightly cheaper than the actual price) and added a custom entry. It wasn't a product sold by weight, but still.

 

I don't mean this in a nebulous sense, like that it's hard to find where things are.

But like, i find scrolling just has too much friction, especially with my small thumbs where i do a lot of flicking rather than sliding.

Anyone else find this?

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