I argue it's still 25%, because the answer is either a,b,c, or d, you can only choose 1, regardless of the possible answer having two slots.
this post was submitted on 06 May 2025
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Yup. And it says pick at random. Not apply a bunch of bullshit self mastubatory lines of thinking. Ultimately, 1 of those answers are keyed as correct, 3 are not. It's 25% if you pick at random. If you're applying a bunch of logic into it you're no longer following the parameters anyway.
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(2 replies)
Since two of them are the same, you have a 50% chance of picking something that is 33% of the possible answers. The other two, you have 25% chance of picking something that us 33% of the possible answers.
So 50%33% + 2 (33%*25%)= 33%
So your chances of being right is 33% cause there is effectively 3 choices.
But that one answer has a 33% larger possibility of being chosen by random, than the remaining two.
I covered that by multiplying it by 50% as it represents 50% of the choices.
Ahhhhhhhhhhhhhhhhh
There's a reason I dropped probability at school.
60%
B) 60% because I'm generally very lucky.
There is absolutely no way it is 60%. Because you can never have 60% chances of picking anything particular when there are only 4 choices. Knowing this, the answer is either 25% or 50%. Two effective choices, so the answer is C, 50%.
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Selecting not at random, A xor D must be correct, because the answer key can only have one correct answer so even duplicate right answers must also be wrong.
It asked for whether the answer is correct not whether it lines up with the answer sheet.
Can I take a 50/50 joker first?
Yes