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Infallible Code (lemmy.ml)

submitted 3 days ago by sirico@feddit.uk to c/programmerhumor@lemmy.ml

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[–] pivot_root@lemmy.world 1 points 3 days ago

you'd end up using modulus and move on quickly.

But where's the fun in that?

There are so many better ~~for obfuscation~~ ways of checking for oddness!

(a & 1) > 0
a.toString()[a.toString().length()-1] - '1' == 0
iseven(a)?(1==0):(1!=0)