this post was submitted on 29 Apr 2025
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1s * (126g/s) * (4.184J/(gC)) * (37C - T) = 524J/C * (37C - T)
120Wh = 432000J
T = -787C
So I guess the math checks out if your city's water supply temperature is way below absolute zero.
Scratch that, let's assume the water actually flows, so T=0C. What water throughout do we need to achieve this level of power consumption?
1s * (X g/s) * (4.184J/(gC)) * (37C) = 432000J
X = 2791g/s = 44gpm
You would have to be showering with 17 showerheads simultaneously using showerheads that are rated at the highest legal flow rates in the US (2.5gpm).
What, you don't shower with 800C steam?